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09-10-2007
| #1 (permalink) |
| Junior Member Join Date: Oct 2007
Posts: 1
 |  Hi everyone I have just started theCity & Guilds 2330 electrical installation on day release from work. I am finding some of the maths a bit tricky.Can anyone out there explain to me how the answer to this maths question was reached R= 17.5X10-9(ohms sign)mX100m __________________________ =1.9ohms 1.5X10-6m2 the 9 and the 6 after the minus signs are written small in the text book i think they are multiplication factors. Thankyou.  |
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18-10-2007
| #3 (permalink) |
| Administrator  Join Date: Jul 2007 Location: South Yorkshire
Posts: 724
 | Re: Hi everyone Hiya padley1786, welcome to the website and I hope you find your answers on this forum. Keep intouch regards Luke (admin) |
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If You Build It, They Will Come n If it aint broken don't fix it!
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22-10-2007
| #4 (permalink) |
| Respected Member Join Date: Sep 2007
Posts: 443
| Re: Hi everyone The small 6 & 9 are called numers of Indices or to the power of. So in your case you have 10-9 or 10 to the power of minus 9 10 -6 or 10 to the power of minus 6 R= 17.5(10-9)x100 / 1.5(10-6)m2 so now it looks like R = 0.00000175 / 1.5(10+12)m (the mSq & 6 are multiplied) now you have R= 0.00000175 / 1500000000000m do the division R= 1.16 Get youself a scientific calculator & ask the lecturer to show how to use the EXP key with the -/+ key & the (bracket) keys for calcs involving indices. The link will take you to a site showing the use of indices in mathmatics. Indices Stick with it I failed maths when I was at school so went to college aged 30 something with no formal maths grade & the best advice my old lecturer gave me was to get hold of some GCSE maths course/revision books from any bookshop & go through them. Also get yourself these two books Electrical Installation Calculations: v. 2 by A.J. Watkins and Russell K. Parton Electrical Installation Calculations: v. 1 by A.J. Watkins and Russell K. Parton Hope thats of some help to you. |
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