Connect 25 AA batteries in parallel and series

[Malooq Omar Tariq]

£1.00 for twenty double aa batteries times 1.5 volts that is thirty volts. £10.00 is 200 aa batteries. 200 aa batteries times 1.5 volts is 300 volts. £5.00 times 20 aa batteries is 100 volts. £20.00 times 20 aa batteries = 400 aa batteries. 400 aa batteries times 1.5 volts = 600 volts.

600 volts into watts is P is power for watts = Volts 600 times I current in amps, 6 = 3,600 watts. To get watts into kilowatt hours, 3,600 divide by 1000 = 3.6 killowatts. 86,400 seconds in 24 hours, divide by 3,600 seconds in one hour, is 24 hours. Total cost is power in kilowatts, 3.6 killowatts x time in hours, 24 x £20.00 batteries = 1728 pence. 1728 pence, /100, 100 pence in £1.00 = £17.28

 

[Malooq Omar Tariq]

£20.00 Battery cost per kilowatt
£20.00 for 600 volts and 400 aa batteries. 600 volts times 2.20 amps = 1,320 watts. To get watts into kilowatt hours, 1,320 divide by 1000 = 1.32 killowatts. £20.00 divide by 1.32 kilowatts = 15.1515151515. £15.15 pence per 1 kilowatt, that is 1000 watts. 1320 watts times 2.20 amps is 600 volts.

 

[Malooq Omar Tariq]

Not wishing to sound rude, but I'm struggling to understand what is it you are trying to achieve.
Are you building a 100 LED light board and seeing if it's cheaper to run of batteries or stepped down mains?
Or are you looking to find the cheapest way to light your property?

I know that electric at 11.871 pence per kilowatt is £8.61 for 24 hours. Then, battery costs £17.28 for 24 hours. Electric for 24 hours, £8.61 - £17.28 for 24 hours from battery makes electric £8.67 cheaper. How do I buy a resistor that is 84 ohms and can handle 600 watts? Thanks for all your help. Enjoy your good week with your loving family and friends.

 

[Paul228]

I think I see what you are trying to do, but STOP !!!!.
You CAN NOT SIMPLY STICK A RESISTOR ACROSS MAINS ELECTRICITY AND HOPE IT WILL POWER YOUR LEDS.
At best you will blow your LEDS to bits. At worse you will KILL yourself.
A little knowledge is dangerous my friend.
If you want cheap led lighting, get on eBay and buy a 5050 LED ribbon and transformer kit ( about £10 to £15)

 

[Bob Geldoff1234]

As they say on Dragons Den....I'm out....

 

[Paul228]

Tell me why I don't like Mondays Mr geldoff

 

[Malooq Omar Tariq]

I think I see what you are trying to do, but STOP !!!!.
You CAN NOT SIMPLY STICK A RESISTOR ACROSS MAINS ELECTRICITY AND HOPE IT WILL POWER YOUR LEDS.
At best you will blow your LEDS to bits. At worse you will KILL yourself.
A little knowledge is dangerous my friend.
If you want cheap led lighting, get on eBay and buy a 5050 LED ribbon and transformer kit ( about £10 to £15)

I am not going to use electric power from electric power plug. I am going to use batteries, 400 aa batteries for £20.00 means 600 volts. To work out watts, 6 ampere times 600 is 3,600 watts. 500 volts for light emitting diodes times 6 ampere is 3,000 watt. 100 volts over and 600 watts over. Work out resistance, equation is R = V divide by I. R is resistance, volts 600 divide by 6 ampere = 100 ohms
Work out current in ampere, equation is I = V divide by R. I is current in ampere, 600 volts divide by 100 ohms = 6 ampere. How can I find a resistor that is 100 ohms and can handle 600 volts please?

Thanks for all your help. Enjoy your happy week and day with your loving family and friends.

 

[Paul228]

Why.
Just use less batteries or instead of wiring all 100 LEDS in series, try doing a combination of series and parallel wiring.
Take a look at this
LED circuit - Wikipedia - https://en.m.wikipedia.org/wiki/LED_circuit

 

[dmxtothemax]

White leds are rated for 2.8 to 3.3v not 5v.
3v is ideal
2 x 1.5v batteries in series = 3v. perfect.
12 x 1.5v battery in parrallel = 1.5v 1.6ah.
make another bank of 12 x 1.5vin parrallel.
we now have two banks of batteries each rated at 1.5v @1.6ah.
put these two banks in series
we now have 3v @1.6ah
if your leds are 1/4W thats 83ma a piece
x 100 = 8.3A
your 1.6ah batteries will last about 12 minutes

 

[Malooq Omar Tariq]

White leds are rated for 2.8 to 3.3v not 5v.
3v is ideal
2 x 1.5v batteries in series = 3v. perfect.
12 x 1.5v battery in parrallel = 1.5v 1.6ah.
make another bank of 12 x 1.5vin parrallel.
we now have two banks of batteries each rated at 1.5v @1.6ah.
put these two banks in series
we now have 3v @1.6ah
if your leds are 1/4W thats 83ma a piece
x 100 = 8.3A
your 1.6ah batteries will last about 12 minutes

Panasonic Eneloop AA pack 8 that have 1900 milliamp hours capacity. Total milliamp hours for 100 light emitting diodes in parallel is 6,000 milliamp hours because 60 milliamp for one light emitting diode times 100 is 6,000 milliamp hours.

Do you think that is better way for more energy in batteries that last a lot longer than alkaline aa batteries that run out of energy after a few uses?

Time that eight panasonic eneloop aa batteries power one hundred light emitting diodes

Eight Panasonic Eneloop AA batteries at 1.20 volts is 17,100 milliamp hours. 17,100 milliamp into amp is 17,100 milliamp divide by 1000 milliamp that is one amp is 17.1 amp hour from eight aa panasonic eneloop batteries. 6,000 milliamp from 100 light emitting diodes divide by 1000 milliamp that is one amp is 6 ampere. 8 AA batteries at 1900 milliamp hours are 17.1 ampere then divide by 6 ampere, that is one hundred emitting diodes means batteries last for 2.85, that is 2 hours and 0.85 times 60 minutes is 51 minutes. Panasonic Eneloop AA batteries cost £11.99 saving £8.01 in comparison to £20.00 worth of AA batteries that make 600 volts.

 

[Besoeker]

Not wishing to sound rude, but I'm struggling to understand what is it you are trying to achieve.

I agree. A succinct and clear description of the project would be a great help. Is it for a Christmas tree, a fish tank, or a pot growing operation? Or all of the above?

 

[Malooq Omar Tariq]

I agree. A succinct and clear description of the project would be a great help. Is it for a Christmas tree, a fish tank, or a pot growing operation? Or all of the above?

It is for anything that I can use light for: for reading books, for taking washing off, for a bike ride, for use as a torch, for decorations on a christmas tree or christmas lights, to grow food indoors and much more.

 

[Taylortwocities]

I cannot be bothered to wade through all of the foregoing as I kind of think i know about Ohms law etc. But, from a practical standpoint, in my view you will be spending most of your free time changing expired batteries.
Dont forget that batteries deplete at different rates, How will you discover which ones need changing, or will you change a hundred batteries at a time?

 

[telectrix]

seems to me a bit like shovelling the ---- out of a cowshed with a teaspoon.

 

[Des 56]

There surely has to be a David Cockburn book on this very subject out there somewhere

 

[Malooq Omar Tariq]

I cannot be bothered to wade through all of the foregoing as I kind of think i know about Ohms law etc. But, from a practical standpoint, in my view you will be spending most of your free time changing expired batteries.
Dont forget that batteries deplete at different rates, How will you discover which ones need changing, or will you change a hundred batteries at a time?

This is why I decide to choose this battery instead, Eight Panasonic Eneloop AA batteries at 1.20 volts gives 15,200 milliamp hours. The Panasonic Eneloop AA batteries are rechargeable up to 2,100 times. 1900 milliamps on single charge times 2,100 is about 3,99,0000 milliamps hours. 3990000 milliamp hours divide by 6000 milliamp hours for one hundred light emitting diodes is 665 hours. The Panasonic Eneloop from 1900 milliamp in five years keeps 70% capacity, that means 0.70% times 1900 milliamp is 1330 milliamps in five years and loses 570 milliamps in five years time.

Update on right milliamps and hours for running one hundred light emitting diodes for the batteries. The batteries in parallel when 15,200 milliamp into amp is 15,200 milliamp divide by 1000 milliamp that is one amp is 15.2 amp hour from eight aa panasonic eneloop batteries. 6,000 milliamp from 100 light emitting diodes divide by 1000 milliamp that is one amp is 6 ampere. 8 AA batteries at 1900 milliamp hours are 15.2 ampere then divide by 6 ampere, that is one hundred emitting diodes means batteries last for 15.2, that is 2 hours and 0.53 times 60 minutes is 31.8 minutes. Panasonic Eneloop AA batteries cost £11.99 saving £8.01 in comparison to £20.00 worth of AA batteries that make 600 volts.

 

[telectrix]

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[Specialist]

@Malooq Omar Tariq : You say that a particular battery loses 30% in five years. You do realise that, this will relate to loss of charge while sitting idle on the shelf ?.
It doesn't mean it will lose 30% over 5 years when under load.
You keep throwing up the same nonsensical figures in post after post, why ?. All this has served to do is waste the time of people that attempted to help you and alienate them.

 

[Specialist]

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View attachment 36589

DITTO.

 

[Rpa07]

Very polite chap, I'll give him that!