all currently working towards my 2391 c&g I&T . I know how to calculate v.d. but the mock test I found online seems a bit out of date or I'm potentially doing something wrong. Here comes de Q.
Voltage drop of a single-phase distribution circuit supplying a power distribution board in a remote building is to be verified as part of the periodic inspection and testing within a workshop complex. The installation forms part of a public 400/230 V TN-S system. The circuit has a measured R1+Rn value of 0.15 Ω and an Ib of 60 A. The circuit protective device has an In of 80 A. What is the voltage drop for this distribution circuit?
mv/A/m × ib × l
1000
According to the mock test the right answer is 10.8V however with result was a little bit higher .
2.8x60x65/1000= 10.92v
Table 4D1B osg
16mm
Mvam 2.8
Could anyone point out where and what I'm doing wrong . TIA
Voltage drop of a single-phase distribution circuit supplying a power distribution board in a remote building is to be verified as part of the periodic inspection and testing within a workshop complex. The installation forms part of a public 400/230 V TN-S system. The circuit has a measured R1+Rn value of 0.15 Ω and an Ib of 60 A. The circuit protective device has an In of 80 A. What is the voltage drop for this distribution circuit?
mv/A/m × ib × l
1000
According to the mock test the right answer is 10.8V however with result was a little bit higher .
2.8x60x65/1000= 10.92v
Table 4D1B osg
16mm
Mvam 2.8
Could anyone point out where and what I'm doing wrong . TIA