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Z = 50R (3,4,5 triangle)
I= V/Z = 400/50 = 8A
P=I^^R = 2560W per phase, 7.68kW total.
...Ah the 3-4-5 triangle a distant math memory ,
(that can be done in head -with a 9 Yumy ) ... Accuracy on anything else (Get-the-app)
Discuss True Power Calculations in the UK Electrical Forum area at ElectriciansForums.net
Z = 50R (3,4,5 triangle)
I= V/Z = 400/50 = 8A
P=I^^R = 2560W per phase, 7.68kW total.
I took the 400V to be the line voltage, whereas you and Jay Spark have taken it to be the phase voltage.
(3 answers now: reminds me of Call My Bluff!)
So using the information that I've gathered from everyone this is my take on the equation, but it seems to differ from the other two haha
P = V x I x pf x 1.73
V = 400V
I = V/Z so: 8A
pf = R/Z so: 0.8
Z = square root of Rsquared + Xlsquared So: 50ohms
So: P = 400 x 8 x 0.8 x 1.73 = 4428.8W
So how come three of us have different answers? And is this the power of one phase? Do i need to multiply this answer by 3 in order to calculate the ENTIRE power of all three phases together?
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