2365 design drawing level 3 Project

[Radoslav]

Hi everyone, I'm new here and was wondering if someone could help to get my college project calculations right.
I'm about to start my 2nd year in my Electrical Apprenticeship and need to complete a small project before end of September.
I have done most of them using the 18th Edition Regs Book and need some help in verifying these numbers as this is the very first time I'm doing this by the book. I am pretty sure I'm on the right path, however there are some things I'm not sure about and not convinced i have used the correct tables/formulas or I have simply made a mistake in my design.
In the attached picture are all my calculations and I will go step by step how I came to these numbers.

1. Ib values are calculated with the following formula - I = P/V. On the lighting circuits I have applied 75% diversity as it is a hotel, but as I am wiring the bathroom fan on the same circuit using a fused spur not sure if diversity is applicable in this case?
2. In values are based on the calculations above.
3. Method of installation is decided as per specification provided with the aid of the regs book
4. Ambient temp is as per specification provided
5. Cable type/insulation taken from the regs book
6. Ca from regs book table 4B2
7. Cg from regs book table 4C1
8. Length based on drawings measurements - not final
9. Volt. Drop from regs book
10. mV/A/m max from On-Site Guide
11. Conductor size chosen based on In - (not sure if my calcs are correct for this so a bit help will be appreciated)
12. It with the aid of the regs book - formula It = In/(Ca*Cg)
13. Iz this is where I'm stuck as I know this should be a tabulated value but I'm struggling with the fact that it's value is smaller than In - (some help to get this right will be needed)
14. Actual Volt. Drop calcs done using the regs book formula - VD = (mV/A/m)*Ib*L/1000
15. Max Disc. Time taken from the regs book
16. Actual Zs calcs done using the On-Site Guide for R1+R2 values and the formula - Zs = Ze+R1+R2
17. Max Zs taken from the regs book table 41.3

Ze value taken from On-Site Guide


Please take a look at my Table and calculations and if you spot something that is incorrect or something that you don't like about the way I have come to this values let me know your thoughts as I want to get a full understanding of how to do all this on my own and of course do it correct.
Thank you.

 

[Eddy Currents]

32A Radials in 2.5?
As a ring is fine but Radials should be 16/20 depending on installation method & factors

 

[davesparks]

32A Radials in 2.5?
As a ring is fine but Radials should be 16/20 depending on installation method & factors

But the stated load is 7kW so a 20A radial would be overloaded, it needs to be 32A for that load.
But yes it is unusual for 2.5mm to be suitable for a 32A radial circuit.

 

[loz2754]

1. It with the aid of the regs book - formula It = In/(Ca*Cg)
2. Iz this is where I'm stuck as I know this should be a tabulated value but I'm struggling with the fact that it's value is smaller than In

It is the tabulated value taken from the appropriate table in the regs before any correction factors are applied.
Iz is the current carrying capacity of the cable after the correction factors have been applied.
See appendix 4 section 3 "relationship of current carrying capacity to other circuit parameters".

 

[Electro-tech]

I would think that the 32A radials should be 4mm minimum in insulation & the deeper the insulation even a 6mm.
Why 2 radials for a Hotel, is this just one room or do you have to cook your own dinner & plug in your kettle?

 

[Radoslav]

Thank you everyone for all the replies. The decision over the cable was made in college and can't remember why we decided to go with 2.5mm. I was thinking at first 6mm or even 10mm based on the length and installation method and my experience, but we were told 2.5mm for some reason and therefore I'm using 2.5mm. I will correct that and maybe go with my first thought of 6mm? The main thing in all this is to show I'm able to use the Regs Book and as it is really the very first time I'm doing this I wouldn't expect my project to be perfect, however I want to know when I'm wrong and try and fully understand why so I can correct myself.
Electro-tech there are 2 radials because columns 1-4 is ground floor and 5-8 is 1st floor.
On the reply from loz2754 I went through the information in the book few times and my understanding is the It value is in table 4D5, and Iz is calculated using the values for Ca and Cg and the formula Iz = Ib/(Ca*Cg)?

PS: English is not my first language and perhaps this could be why at first I couldn’t fully understand why It is the tabulated value from table 4D5 as in the table clearly says “current-carrying capacity” which is marked with Iz.

 

[davesparks]

1. Conductor size chosen based on In - (not sure if my calcs are correct for this so a bit help will be appreciated)

This may the start of your problem, you don't select conductor size based on In, you select your conductor size after doing the next step.

1. It with the aid of the regs book - formula It = In/(Ca*Cg)

You've misread the equation, it is It > In/(Ca*Cg) (actually its greater than or equal to but I don't know how to type that on the phone)
It is the tabulated CCC of the cable, literally the number printed in the table.

So what you do is calculate In/(Ca*Cg) and then look up the cable size which has an It which is the next highest, or equal to, the product of that calculation (which I don't think actually has a symbol)

The use of the rating factors can be a bit confusing at first and is often not taught very well. We take the nominal current of the circuit and apply factors to that which will either increase it or reduce it, and then use this modified value to select the cable size (unless we can calculate based on design current)
So if we have an In of 6A and have a combined rating factor of 0.5 we select a cable that can carry a current of 12A (6A/0.5=12A)

1. Iz this is where I'm stuck as I know this should be a tabulated value but I'm struggling with the fact that it's value is smaller than In - (some help to get this right will be needed.

Iz is the CCC of the cable after rating factors have been applied, you can calculate this seperately to the cable selection process by applying the rating factors to It.

 

[davesparks]

View attachment 100377

For circuit 1:
In = 6A
Ca = 0.89
Cg = 0.65

So we calculate:
=In/(Ca*Cg)
=6/(0.89*0.65)
=6/0.5785
=10.37
But we need a whole number so we round it to 10

Now we go to table 4D5 and look down the column for method 103 and find a cable which has a CCC greater than or equal to 10A
Thus we select 1.5mm as it has an It equal to 10A

 

[davesparks]

View attachment 100377

Next piece of the puzzle, I can see where your calculation has gone wrong.

You've got a figure of 4.38 in your It row for circuit 1 which suggests you've made a mathematical error in applying the formula.

You've tried to calculate 6/(0.89*0.65) but have actually calculated 6/0.89*0.65

Where an equation contains brackets you need to do the calculation within the brackets first and then continue with the rest of the calculation.

I used to struggle with this kins of maths and found it helped me to write out calculations the way I did in the post above. So wrote the equation, then write it with the symbols replaced by the actual values on the next line then continue with a new line for each step of the calculation.

Spreadsheets are good and certainly have their uses, but when you are learning you will find a lot of value in putting pen to paper and doing the calculations long-hand.

 

[davesparks]

but we were told 2.5mm for some reason and therefore I'm using 2.5mm. I will correct that and maybe go with my first thought of 6mm?

Who told you 2.5mm? If it was the college tutor then I'd be a bit concerned about their knowledge. Even if it was a genuine mistake, which we all make, then 2.5mm for a 32A radial would make anyone stop and double check (except in particular circumstances maybe)

Don't go with guesses or what just sounds right, go through the calculations as I did above and work out the right answer.
College projects will often be deliberately designed to give some unusual/unexpected cable sizes as a way of making sure you are actually doing the calculations and not just filling in boxes with what sounds right for a circuit.