Discuss How to check the Wattage of a scrapped resistor? in the UK Electrical Forum area at ElectriciansForums.net

I couldn't sleep. The more I think the more I realize its much more simpler.
I strongly believe the absolute necessary components to measure a resistor Wattage is down to 3 esential elements in the circuit:
1 - a variable voltage supply; 2- the test resistor itself; 3- a measuring tool of some kind.
Actually there are 2 or 3 measuring tools we need: the Ampmeter, Voltmeter and Thermometer. So 5 components for the final and complete circuit.
Here is a more refined idea that I imagined:
View attachment 102109
Also, doen't matter the 'range' of resistors used with this type of circuit.
That will give you the wattage for 100C operation which is usually OK, but as @Lucien Nunes points out the actual wattage to meet and given specification might be rather different.

Also for some resistors, especially smaller SMD types, the "safe and reliable operation" voltage limit can be fairly low and it might be your limiting factor instead of temperature.
 
Here's a typical data sheet for a particular series of power resistors.
VTM power resistor data

Note the power derating graph. The maximum working temperature is 275°C and the ratings are based on this. If you were to test based on 100° maximum you would get a much lower rating at the typically quote ambient options of 40° or 70°, which is why you need to identify the construction to make an informed guess at the permissible temperature. E.g. with linear derating, (275-70)/(100-70) = 6.8 i.e. the real 70°C power rating would be nearly 7 x higher than the one you 'measured.'
 
I didn't do any measurement yet. I was trying to figure out what the circuit may look like. To get an estimate of a component power. I'm not after exact values. But if I get it exact, Ill be equally happy. I put an arbitrary 100°C but that will be changed when the actual experiment will start.
 
But you can't find out the maximum permitted temperature from the experiment, other than by when the part starts smoking, breaks in half or goes out of tolerance. Just like car manufacturers test prototypes with crash-test dummies, resistor manufacturers have to cook a lot of resistors to find out what power they would withstand. That is why you either need the data sheet or experience of resistors, or a direct comparison to one of similar construction.
 
mister @Lucien Nunes , I understand everything you said so far and you explained clear and logical enough. Thank you for that. My intention here is to get an idea and the hope is to get close enough to the original value. Not by any means to be perfect on the spot. If it will fail, it will fail, but I give it a try. I'm as curious as you what the real experiment will give me. You are more skeptical than curious but lets say you are curious. Haha.
 
I've done it for you to prove the point: see attached pics.
Resistor A / left PSU: 2.13W.
Resistor B / right PSU: 2.02W
Resistor C (not shown) : 2.08W
All three are at 100 +/-2 °C
From those figures, tell me which resistor is rated at 1W, which at 2W and which at 3W?
See the problem?
20221003_144930.jpg
20221003_145033.jpg
 
Aaah you are fast. Thank you for playing. Really.
I did the test as well just now.
We will compare notes and the math guys should jump into this data I collected. Also yours.
---
edited some minutes later:
Yes, I confirm your calculations:
1664824340791.png

From those figures, tell me which resistor is rated at 1W, which at 2W and which at 3W?
See the problem?
We are definitely miss a variable that will give us the Wattage. Is my strong belief. But what is it?
 
Last edited:
We are definitely miss a variable that will give us the Wattage. Is my strong belief. But what is it?

It's what I've been saying all along - the maximum working temperature.

This depends on the type of materials used and the quality and method of construction of that particular resistor. For example, a silicone-coated wirewound will typically withstand 250°C or even 300° with no problems, but a carbon composition might fail rapidly at 120°. And with encased resistors there can be significant thermal resistance from the element to the dissipative surface, so the critical temperature (of the element) might be significantly higher than the temperature of the case.

My three samples all achieved nearly the same dissipation at the same temperature, meaning that they all have nearly the same thermal resistance from case to ambient. That is to be expected, because they are all the same size with similar radiation characteristics. The ambient temp was 18°C so the thermal resistance of all of them is about (100-18)/2 = 41°C/W. This gives the gradient of the line in the derating graph while the max temp gives its X-intercept.

The 1W was resistor C, a ceramic-cased carbon composition made in the 1960s. It's working temperature is limited by the tendency of the slug material to change in characteristics. Above its rated temperature, it will tend to drift badly out of tolerance, both reversibly with temperature change and permanently, and have a shortened life. At 2W it started oozing wax.

The 2W was resistor A, a carbon film type. These are more stable and can work at a higher temperature,. If overrun, the first thing to burn is usually the paint, even while the element stays in tolerance. They are not however as resistant to high pulse dissipations as carbon compositions.

The 3W was resistor B, a metal oxide film type. These have generally better characteristics than carbon-film, lower noise, better tempco and long-term stability, higher working temp. This one would probably withstand 6W or even 9W, 3x its rated dissipation, for a short time (its life span might be reduced) although the coloured bands would burn off. At that power, if mounted on a PCB it would scorch the PCB and the leads would desolder themselves but the resistor would survive. In the 1970s there were wirewound resistors in TVs with a thermal cutout that worked by desoldering a spring-loaded contact if the resistor overheated due to a fault in the line output stage.

So there you have it - you need at least two parameters to determine the rating (at a given ambient temperature):
  • Thermal resistance to ambient (which we find out with the heating test but all similar case sizes will have similar thermal resistances.
  • Maximum working temperature (which comes from manufacturer data or comparison with other resistors of similar construction)
 
Thank you again for playing. Nice explanations !
I did some advances as well. Very unorthodox ones. With some good and consistent result --over the same category-- of the component - for example only over all 1/8 0.125W ones. But when I expected the same result over the larger ones, the 0.250W, it didnt work. But I got somewhat close. I could touch it but not grab it. Aaah... so close. Here is the data: link Tell me what you think if you get through it. Thanks. My best friend, mister @Lucien Nunes !!!
 
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