back to basics higher the volts lower the amps?

[Scud]

Somebody needs to rewrite the equation P = I x V then . Power (the rate of energy dissipation) is a combination of current and voltage. Energy use, as you correctly say is, a combination of power and time.

I think I put my point across badly.Perhaps I need to rephrase. Even if the faulty supposition that a decrease in voltage would lead to an increase in current, the number of units used would be the same or arguably less. The kilowatt hour meter registers the product of voltage, current and time. Does that make my point clearer?