@justcurioustwo why don’t you build it.....film it......and prove all us doubters wrong?
This is a simply mechanical machine that utilized the rising force of balloons with air in them. You can also envision this as inverted umbrellas. What makes this “work” is the combining lifting force of multiple umbrellas with expanding air in them. The result is an increase in “force”; that I am now trying to convert into watts and the speed these rising balloons are traveling.
Maybe someone here with more technical knowledge can help me out in this. Once done we can the evaluate whether it is a zero-sum game or whatever.
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But the problem is that the energy used to move the air to the bottom of the system will be more than the energy output from the system.
The balloons will expand yes, but the amount of air in them will remain the same, it will just be less compressed. The lifting force won't change as it rises.
You state that the lifting force will not change as the balloons expand. This might be my Achilles heel. The lifting force is equal to the water being displaced. At 1 ATM the volume of air under this umbrella is 300 cubic feet. This same 300 cubic feet if air under an umbrella at a depth of 594 feet is under a pressure of 264.6 p.s.i.; has a volume of 16.66 cubic feet.
As the umbrella rises the air bubble expands pushing out more water.
If I understand your statement correctly, please tell me how a balloon displacing 16 cubic feet has an equal rising force of a balloon displacing 100 cubic feet?
I am sure I am wrong, and you are right but just saying so is not convincing enough for me.
Please elaborate on your point of view.
Thanks in advance.
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There is one more thing I need help on, and this is the place I can get it. I am trying to compute two values.
[1] The electrical output of this machine.
[2] The speed of the rising bubbles.