_q12x_
DIY
- Reaction score
- 212
I cant say I clearly understand ALL that you said here.If you have 8 n channel power mosfet then but these can be connected common source to the 0V rail and a 1kR resistor inserted between each drain and the 5V rail.
Four of the mosfet have their gates driven by A, B ,C and D outputs of the 7493 and the other four by A*, B*, C* and D* derived from the four inverter gates you currently use. You can dispense with the 4 pnp transistors.
Connect the first 4 mosfet drains to the current logic busbars and the second 4 mosfets drains to a new set of 4 logic busbar. Now you can connect the 4 input dtl NAND with led as required to 4 of these 8 busbar to select the right 4 term logic operand term for the led. The eight busbars provide A, B, C, D, A*, B*, C* and D* the logic signals.
With this scheme you can avoid using dtl NOT gates.
You are more clear in drawing cct than writing !!!
But I get the hint from your reading here, even if I dont completely understand it. To use mosfets as HIGH and LOW switching for the 4line bus. And most probably the other 4 you mention to be the 0V gate discharge. Its how I see it.
I will draw a quick cct of how ---I--- believe this should be. If its exactly as you explained here, then my sub-conscientious brain understood it, not the conscientious one. Haha.
Update soon.