Discuss Adiabatic equation in the UK Electrical Forum area at ElectriciansForums.net

Zs=0.04Ω
V= 230V

230/0.04= 5750A

-----------------

I=5750A
T= 0.025s (Read this from you post, also agrees with regs)
K=115


S = ((5750²)x0.025)
-----------------
115

S= 7.906 mm²

So with a 10mm² you will be oversized by 21%.

-----------------------------------------------

If you want to use the Steel armoured of the SWA:

I=5750A
t=0.025s
K=51 (assuming thermoplastic)

S = ((5750²)x0.025)
-----------------
51

S= 17.827 mm²

If you're thinking 'Jesus Christ that seems small' remember that the cpc only has to take this fault current for 0.025 seconds. And 21% is a nice amount of headroom, only if the result was borderline would I move up too the next size.

I presume you got the result:

S= 15.811mm² ????

That's because you used 0.1 as the value of 't' instead of 0.025. t is the actual disconnection time for your PFC (not maximum allowed or anything else). The actual disconnection time can be found by looking at the disconnect time curves in the reg, or better still from the manufacturers data sheet.

Hope that helps. =)
 
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