Discuss MCS Guide to the installation of Photovoltaic systems (shading analysis) in the Solar PV Forum | Solar Panels Forum area at ElectriciansForums.net

I've been learning how to use SketchUp 3D Modeling with Geo Location via google earth. Its a brilliant and free tool....but to do accurately does take a lot of time....and you need accurate measurements.

And on side but related issue......Will products such as SolarEdge and Micro Inverters now become more popular and if so how would we account for them in calculations...
 
And what about shading from clouds.....Impossible to avoid shading altogether when the sun goes behind a cloud and you can see the shadows move across the roof...
 
I'm a expert on sketch-up and have been using it before we started solar pv however my question is, it still takes time to build then all the other paperwork. Is there margin in pv to do it, when you compete with bob the builder/double glazer working off a ladder !
 
Quote
(I've created a film version of the shading diagram to fit the Solar Shading Meter : Solar Shading / PV Horizon Meter

Works OK, and can give a photocopy of the results to the client. Need an upstairs window close to the array for it to be of any use whatsoever... And there's still the challenge of what if the array doesn't face south......)

Most likely Submarine type Periscope fitted with PV Horizon Meter on the top.
 
I've been testing it out on a couple of projects and would appreciate a sense check by someone on a calculation for an aerial.

4kWp
Location 11
pitch - 40 d
Azu - 40 d
Angle above horizon 45 d
Aerial Sited at 20 d west of South

= 4 (kWp) x 849 (Kk) x 0.69 (SF) = 2343kWh

Is this right??
 
:thinking:.....there is no way a tv aerial would cause 31 % shading losses. Is the tv aerial coming into 31 of the boxes for the shading horizon? If so then if using this method (which I for one am not) then I'd suspect that shading losses would be moe like 10% probably a bit less.

Another reason why the shading analysis is at best a draft version for an undergraduate degree thesis, maybe even A level project maybe even GCSE project.
 
PVsol for my Sharp NU180E & SMA 400tl reckon I should be getting 2800ish kwh/pa using SAP 2012 for NW England. Strange that with a phone line running diagonally across the whole of the array I've had 7685kwh in 29 months, the first ones of which were Nov, Dec & Jan .........
 
I've been testing it out on a couple of projects and would appreciate a sense check by someone on a calculation for an aerial.

4kWp
Location 11
pitch - 40 d
Azu - 40 d
Angle above horizon 45 d
Aerial Sited at 20 d west of South

= 4 (kWp) x 849 (Kk) x 0.69 (SF) = 2343kWh

Is this right??
have you worked this out as if the aerial is a solid object?

Obviously it's wrong in reality, I'm just checking how you've worked it out using the new / already badly outdated methodology to see if it really is that bad or not.
 
How have I worked it out...?

The aerial is about 1 ft from the bottom of the array and the top of the aerial is at a 45 degrees from the bottom of the array.

I have plotted a line from the bottom of the chart to the 45 degrees line and then drawn a circle to see which areas the path of shading will hit - 31 squares in total through out the course of the day.

:willy_nilly:
 

Reply to MCS Guide to the installation of Photovoltaic systems (shading analysis) in the Solar PV Forum | Solar Panels Forum area at ElectriciansForums.net

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