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Discuss volt drop calcs and 230 v in the UK Electrical Forum area at ElectriciansForums.net
What do the IET expect to happen where this occurs? Im a little confused here. If l listen to my maths teachers from sparky college, he said that a voltage drop can cause a circuit to overload.
Is that whats happening here, at the transformer perhaps? Ive no idea personally and would love to know the answer as ive never seen 223V anywhere before. Always been 236-253V...
I think your maths teacher needs to think about this "overload" comment, it's simply incorrect. A drop in the voltage will cause the load to decrease.
Time you learnt about workload and efficiency. Not every load is resistive, in fact most aren’t.
Take a motor, input power = output power – efficiency.
1KW at the shaft needs 1KW feed in to the motor and a bit more for the losses.
1KW = 1000W no mater how you look at it.
With these points made, how would a lower voltage on a given size of motor result in a greater current? What happens if a 240V voltage is placed across the coil of a 24V relay? The relay will have a stated holding current at its nominal voltage (24V) but applying 240V won't reduce this current ten fold to keep the coil power consumption constant.
This is the same as another post in which this came up. Items on electrical equipment are given a power rating according to a nominal voltage, they do this as voltages are never constant. True
With no voltage applied a motors windings are a theoretical linear load, once voltage is applied the load becomes inductive and so the impedance opposes the flow of current and and limits it. Even with no rotor, a motors windings will limit the flow of current. Try it, keep a fire extinguisher handy
Once a rotor is introduced, the windings induce a voltage (and so a current) within it and as the sine wave of the supply voltage fluctuates at the given frequency, the rotor tries to keep up. As the load on the motor is increased, the slip of the rotor increases also and with this there is a greater difference in speed between the supply frequency and rotor, creating a larger current in the rotor. You need a slipring motor to prove the rotor currents. You may be surprised by the readings for slip current.
With these points made, how would a lower voltage on a given size of motor result in a greater current? What happens if a 240V voltage is placed across the coil of a 24V relay? The relay will have a stated holding current at its nominal voltage (24V) but applying 240V won't reduce this current ten fold to keep the coil power consumption constant.
Although a motors load may indeed be constant at 1kW, this does not mean the voltage and current will flex to meet this fixed load. A motor may be capable of providing the torque to meet a load of 1kW at a given geared speed negating the slip. This very same motor may be incapable of generating the torque at a few volts less as it would simply stall if the voltage was not high enough to generate a high enough current to drive the load before losses.
You will never escape:
Power in = Power out + losses
If a motor is loaded at 100% of its rating, it must be supplied with its rated nominal voltage or higher to drive the load. A lower voltage will not just simply result in a constant power output through an increased current.
Want to rethink that?
I think the time for me to learn has passed and it is you who needs more time to learn.
The question is, do you understand enough electrical theory to work this out from first principles?
It depends on the 'item'. A heating element connected to the mains will pass a current that increases with rising voltage. A laptop power supply will pass a current that decreases with rising voltage. If you understand how something works you can calculate how its current will vary.
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